Question

A circuit artist is climbing a $20m$ long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is ${30}^o$.

Answer 1

Let $AB$ be the pole and $Ac$ be the rope making angle ${30}^{\circ }$

In

I$\begin{array}{c}\Delta ABC\\ \frac{AB}{AC}=\sin {30}^{\circ }\\ \Rightarrow \frac{AB}{20}=\frac{1}{2}\\ \Rightarrow AB=\frac{20}{2}\\ \Rightarrow AB=10m\end{array}$

Therefore, height of the Pole is $10m$.