A circuit consists of a 2 - F capacitor connected through an a-c ammeter to an a-c- source of voltage given by V -200 -2sin 100 t - - 3 where V is volts and t in seconds- The reading of the ammeter isA- 10 mAB- 40 mAC- 20 mAD- 30 mA

The correct option is B 40 mA An a.c. ammeter reads the rms value of current. Given V_0 = 200 √(2) Volts and ω nbsp; = 100 rad s^ 1. I_rms= V_rms× nbsp;ω ...

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Byju's Answer

Standard XII

Physics

Capacitive Reactance

A circuit con...

Question

A circuit consists of a $2 μ F$ capacitor connected through an a.c ammeter to an a.c. source of voltage given by $V = 200 \sqrt{2} s i n (100 t + π / 3)$ where $V$ is volts and $t$ in seconds. The reading of the ammeter is

$10 m A$

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$20 m A$

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$30 m A$

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$40 m A$

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Solution

The correct option is D
$40 m A$

An a.c. ammeter reads the rms value of current.

Given $V_{0} = 200 \sqrt{2}$ $V o l t s$ and $ω = 100 r a d s^{- 1} .$

$I_{r m s} = V_{r m s} \times ω C$

$= \frac{200 \sqrt{2}}{\sqrt{2}} \times 100 \times (2 \times 10^{- 6}) = 40 m A$

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A circuit consists of a 2μF capacitor connected through an a.c ammeter to an a.c. source of voltage given by V=200√2 sin(100t+π/3) where V is volts and t in seconds. The reading of the ammeter is

The correct option is D 40 mA An a.c. ammeter reads the rms value of current. Given V0=200√2 Volts and ω=100 rad s−1. Irms=Vrms×ωC =200√2√2×100×(2×10−6)=40 mA

A circuit consists of a $2 μ F$ capacitor connected through an a.c ammeter to an a.c. source of voltage given by $V = 200 \sqrt{2} s i n (100 t + π / 3)$ where $V$ is volts and $t$ in seconds. The reading of the ammeter is

The correct option is D
$40 m A$

An a.c. ammeter reads the rms value of current.

Given $V_{0} = 200 \sqrt{2}$ $V o l t s$ and $ω = 100 r a d s^{- 1} .$

$I_{r m s} = V_{r m s} \times ω C$

$= \frac{200 \sqrt{2}}{\sqrt{2}} \times 100 \times (2 \times 10^{- 6}) = 40 m A$