Question

A circuit consists of a resistor of 1 ohm in series with a parallel arrangement of resistors of 6 ohms and 3 ohms. Calculate the total resistance of the circuit. Draw a diagram of the arrangement.

Answer 1

6 Ω and 3 Ω resistors are in parallel, so their equivalent resistance is given by

$\frac{1}{R}=\frac{1}{6}+\frac{1}{3}\Rightarrow R=2\Omega$

This 2 Ω resistance is connected with 1 Ω resistance in series.

So, equivalent resistance of the network = 2 Ω +1 Ω = 3 Ω