A circuit consists of three batteries of emf E1 - 1 V- E2 - 2 V and E3 - 3 V and internal resistances 1 - 2 - and 1 - respectively which are connected in parallel as shown in the figure- The potential difference between points P and Q is

The correct option is B 2.0 VThe equivalent emf of three non ideal cells is given by #160; E=E_1r_1+E_2r_2+E_3r_31r_1+1r_2+1r_3 =11+22+3111+12+11V ...

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Byju's Answer

Standard XII

Physics

Parallel Combination of Cells

A circuit con...

Question

A circuit consists of three batteries of emf $E_{1} = 1 V, E_{2} = 2 V$ and $E_{3} = 3 V$ and internal resistances $1 Ω, 2 Ω$ and $1 Ω$ respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is

1.0 V

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2.0 V

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2.2 V

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3.0 V

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Solution

The correct option is B 2.0 V
The equivalent emf of three non-ideal cells is given by
$E = \frac{\frac{E_{1}}{r_{1}} + \frac{E_{2}}{r_{2}} + \frac{E_{3}}{r_{3}}}{\frac{1}{r_{1}} + \frac{1}{r_{2}} + \frac{1}{r_{3}}}$

$= \frac{\frac{1}{1} + \frac{2}{2} + \frac{3}{1}}{\frac{1}{1} + \frac{1}{2} + \frac{1}{1}} V$

$= \frac{5}{5} \times 2 V$
$= 2 V$

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A circuit consists of three batteries of emf E1=1V,E2=2V and E3=3V and internal resistances 1Ω,2Ω and 1Ω respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is

The correct option is B 2.0 VThe equivalent emf of three non-ideal cells is given by E=E1r1+E2r2+E3r31r1+1r2+1r3=11+22+3111+12+11V=55×2V=2V

A circuit consists of three batteries of emf $E_{1} = 1 V, E_{2} = 2 V$ and $E_{3} = 3 V$ and internal resistances $1 Ω, 2 Ω$ and $1 Ω$ respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is