A circuit contains a battery with a terminal voltage of $4 v o l t s$ and a four-ohm resistor.
If the internal resistance is two ohms, what is emf?

4 v o l t s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 v o l t s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 v o l t s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 v o l t s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $6 v o l t s$
Given : $R = 4$ ohms $r = 2$ ohms
Terminal voltage of the battery $V = 4$ volts
Thus current through the circuit $I = \frac{V}{R} = \frac{4}{4} = 1$ amp

Hence emf of the battery $E = I (R + r) = 1 \times (4 + 2) = 6$ volts

Suggest Corrections

Similar questions

Q. Internal resistance of a battery of 2volt terminal voltage is 0.2 ohm and current following through it is 0.5A.So emf of the battery will be:

Two identical cells, each of emf 2 V and of unknown internal resistance r are connected in parallel. This combination is connected to a 4 ohm resistor. If the terminal voltage across the cells in the closed circuit is 1.5 V then the internal resistance of the cell is

A storage battery has e.m.f. $15$ volt and internal resistance $0.05 o h m$ . Its terminal voltage when it is delivering $10$ ampere is:

Q. The circuit shown in the figure contains two diodes each with a forward resistance of

50

ohms and with infinite backward resistance. If the battery voltage is

6

V, the current through the

100

ohm resistance (in Amperes) is?

Q. A battery of emf

2

volt and internal resistance

0.1

ohm is being charged with a current of

5

ampere. The potential difference between the two terminals of the batteries is

Join BYJU'S Learning Program

A circuit contains a battery with a terminal voltage of 4volts and a four-ohm resistor.If the internal resistance is two ohms, what is emf?

The correct option is C 6voltsGiven : R=4 ohms r=2 ohms Terminal voltage of the battery V=4 voltsThus current through the circuit I=VR=44=1 ampHence emf of the battery E=I(R+r)=1×(4+2)=6 volts

A circuit contains a battery with a terminal voltage of $4 v o l t s$ and a four-ohm resistor.
If the internal resistance is two ohms, what is emf?

The correct option is C $6 v o l t s$
Given : $R = 4$ ohms $r = 2$ ohms
Terminal voltage of the battery $V = 4$ volts
Thus current through the circuit $I = \frac{V}{R} = \frac{4}{4} = 1$ amp

Hence emf of the battery $E = I (R + r) = 1 \times (4 + 2) = 6$ volts