A circuit contains an ammeter, a battery of 30V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and as shunt of 20 ohm, the reading in the ammeter will be:
A
1A
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B
0.5A
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C
0.25A
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D
2A
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Solution
The correct option is B0.5A Resistance of ammeter: ram=480×20480+20=19.2 Current : i=3040.8+19.2=0.5amp