A circuit contains two capacitors in parallel wired in series to a resistor and source as shown above. The capacitors are initially uncharged.
Which of the following describes the current I through and voltage $V_{C}$ across the Capacitor $C 1$ after the circuit reaches steady state?

I = 0, V_{C} = 0

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I = 0, V_{C} = V

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I = 0, V_{C} = \frac{V}{2}

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I = \frac{V}{R}, V_{C} = 0

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I = \frac{V}{R}, V_{C} = V

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Solution

The correct option is B $I = 0, V_{C} = V$
When the steady state is reached , no current flows in the circuit as capacitors are charged now ,therefore voltage drop across the resistors becomes (as current in resistors is zero) , and voltage $V_{C}$ , across capacitor $C_{1}$ equalises the battery emf, which is $V$ .i.e. $I = 0, V_{C} = V$

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