wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A Circuit contains two identical resistors of resistance R and a capacitor of capacitance C1 connected to a battery that provides an emf of V, as shown above.
At time zero the Capacitor is initially uncharged. Which of the following expressions would represent the power dissipated in resistor R2 after a long time?
496366.png

A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1eRC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
V2R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
V22R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
V24R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0
After a long time steady state is reached , now the voltage across capacitor is constant (equal to the voltage of battery) hence current (which is a time derivative of voltage ) becomes zero . Therefore power dissipated in resistor would become zero as P=I2R or P=02×R=0

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Important Quantities
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon