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Question

A circuit contains two inductors of self-inductance L1 and L2 in series (see figure). If M is the mutual inductance, then the effective inductance of the circuit shown will be

A
L1+L2
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B
L1+L22M
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C
L1+L2+M
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D
L1+L2+2M
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Solution

The correct option is D L1+L2+2MSeries connection of 2 inductors can be divided into two categories. Case 1: When current through both the inductors is in same direction. Effective inductance of the circuit, L=L1+L2+2M Case 2: When current through both the inductors is in opposite direction. Effective inductance of the circuit, L=L1+L2−2M Since for the circuit given in he question belongs to 1st case. Therefore effective inductance of the circuit, L=L1+L2+2M

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