Question

A circular area of diameter $d$ is vertical and submerged in a liquid. Its upper edge coincides with the liquid surface. The centre of pressure from the liquid surface is at a depth of :

• A. $d/2$
• B. $\frac{3d}{7}$
  
• C. $\frac{3d}{4}$
  
• D. $\frac{5d}{8}$
  

Answer 1

The correct option is D $\frac{5d}{8}$



$h^{\ast }=\overline{h}+\frac{I_G}{A\overline{h}}$

$=\frac{d}{2}+\frac{\left(\frac{\pi d^4}{64}\right)}{\frac{\pi }{4}{d}^2\times \frac{d}{2}}=\frac{d}{2}+\frac{d}{8}=\frac{5d}{8}$