A circular beam of diameter 2cm falls on a plane surface of glass. The angle of incidence is 60∘ and μ=32 for the glass. The diameter of the refracted beam is
A
4 cm
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B
3 cm
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C
3.26 cm
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D
2.52 cm
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Solution
The correct option is C 3.26 cm μ=sinisinr=sin60∘sinr32=√32[1sinr];sinr=1√3cosr=√2√3d2=d1[cosrcosi]=d1[cosrcos60]=2[√2√312]=4√2√3=4×1.4141.732d=3.26cm