A circular coil A has a radius $R$ and the current flowing through it is $I$ . Another circular coil B has a radius $2 R$ and the current flowing through it is $2 I$ , then the magnetic fields at the centre of the circular coils are in the ratio of :
(i.e. $B_{1}$ to $B_{2}$ )

4 : 1

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2 : 1

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3 : 1

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1 : 1

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Solution

The correct option is D $1 : 1$
Magnetic field due to circular coil is given by,
$B_{1} = \frac{μ_{0} I}{2 R}$
$B_{2} = \frac{μ_{0} (2 I)}{2 (2 R)}$
$(B_{1} : B_{2}) = 1 : 1$

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A circular coil A has a radius R and the current flowing through it is I. Another circular coil B has a radius 2R and the current flowing through it is 2I, then the magnetic fields at the centre of the circular coils are in the ratio of : (i.e. B1to B2)

The correct option is D 1:1Magnetic field due to circular coil is given by,B1=μ0I2RB2=μ0(2I)2(2R)(B1:B2)=1:1

A circular coil A has a radius $R$ and the current flowing through it is $I$ . Another circular coil B has a radius $2 R$ and the current flowing through it is $2 I$ , then the magnetic fields at the centre of the circular coils are in the ratio of :
(i.e. $B_{1}$ to $B_{2}$ )

The correct option is D $1 : 1$
Magnetic field due to circular coil is given by,
$B_{1} = \frac{μ_{0} I}{2 R}$
$B_{2} = \frac{μ_{0} (2 I)}{2 (2 R)}$
$(B_{1} : B_{2}) = 1 : 1$