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Question

A circular coil carrying a current I has radius R and number of turns N. If all the three, i.e., the current I, radius R and number of turns N are doubled, then magnetic field at its centre becomes.

A
Double
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B
Half
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C
Four times
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D
One fourth
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Solution

The correct option is B Double
Magnetic field at the center of coil is given by B=μNI2R
New current I=2I
New radius R=2R
New number of turns N=2N
Thus, magnetic field B=μoNI2R=μo(2N)(2I)2(2R)
B=2×μoNI2R=2B
Thus magnetic field gets doubled.

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