A circular coil of 20 cm2 area is made of 100 turns as shown in figure- In 0-2 s of time- B reverses its direction of the field- How much charge flows through wire if resistance R is 6 -

EMF, e = N ( ΔϕΔ t ) nbsp; So, i = eR = NR ( ΔϕΔ t ) Charge flown, Δ q = i Δ t = N ΔϕR = 100 × 9.6×20×10^ 46 =0.32 C ...

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Standard XIII

Physics

Using Lenz's Law

A circular co...

Question

A circular coil of $20 {cm}^{2}$ area is made of $100$ turns as shown in figure. In $0.2 s$ of time, $\to B$ reverses its direction of the field. How much charge flows through wire if resistance $R$ is $6 Ω$ ?

0.32 C

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0.64 C

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0.28 C

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0.16 C

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Solution

The correct option is A 0.32 C
EMF, $e = N (\frac{Δ ϕ}{Δ t})$
So, $i = \frac{e}{R} = \frac{N}{R} (\frac{Δ ϕ}{Δ t})$

Charge flown, $Δ q = i Δ t$
$= \frac{N Δ ϕ}{R} = \frac{100 \times 9.6 \times 20 \times 10^{- 4}}{6}$
$= 0.32 C$

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A circular coil of 20 cm2 area is made of 100 turns as shown in figure. In 0.2 s of time, →B reverses its direction of the field. How much charge flows through wire if resistance R is 6 Ω?

The correct option is A 0.32 CEMF, e=N(ΔϕΔt) So, i=eR=NR(ΔϕΔt) Charge flown, Δq=iΔt =NΔϕR=100×9.6×20×10−46 =0.32 C

A circular coil of $20 {cm}^{2}$ area is made of $100$ turns as shown in figure. In $0.2 s$ of time, $\to B$ reverses its direction of the field. How much charge flows through wire if resistance $R$ is $6 Ω$ ?

The correct option is A 0.32 C
EMF, $e = N (\frac{Δ ϕ}{Δ t})$
So, $i = \frac{e}{R} = \frac{N}{R} (\frac{Δ ϕ}{Δ t})$

Charge flown, $Δ q = i Δ t$
$= \frac{N Δ ϕ}{R} = \frac{100 \times 9.6 \times 20 \times 10^{- 4}}{6}$
$= 0.32 C$