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Question

A circular coil of 20 turns having radius 10 cm is placed in a uniform magnetic field of 0.2 T normal to the plane of the coil, If a current of 5 A passes through the coil, then the torque experienced by the coil in (Nm)

A
0.314
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B
0.928
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C
0.628
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D
0.528
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Solution

The correct option is C 0.628
Given,

N=20 turns ; r=10 cm=10×102 mB=0.2 T ; A=πr2=π (10×102)2=π×102 m2i=5 A ; θ=90

Torque experienced by the coil is,

τ=M×B=MBsinθ

τ=NiABsinθ

=20×5×π×102×0.2×1

=2×3.14×101

=0.628 Nm

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

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