Question

A circular coil of cross-sectional area $20c{m}^2$ and $20$ turns is rotated about the diameter with angular speed of 50 rad $s^{-1}$ in a uniform magnetic field of magnetic $3.0\times {10}^{-2}T$. Calculate the maximum value of the current in the coil.

Answer 1

Here, $A=200c{m}^2$

$N=20$

$w=50\frac{rad}{s}$

$B=3\times {10}^{-2}T$

For maximum current emf should be maximum.

So for maximum emf $e=NABwsinwt$

$sinwt=1$

$e_{max}=NABw$

$e_{max}=20\times 200\times 10\ast -4\times 50\times 3\times {10}^{-2}$

$e_{max}=0.6V$

Since resistance is not given,let us consider $R$

$i_{max}=\frac{e_{max}}{R}=\frac{0.6}{R}$