Question

A circular coil of cross-sectional area $200c{m}^2$ and 20 turns is rotated about the vertical diameter with angular speed of $50rad{s}^{-1}$ in a uniform magnetic field of magnetic $3.0\times {10}^{-2}T$ . Calculate the maximum value of the current in the coil.

Answer 1

Here, $A=200c{m}^2$

$N=20$

$\omega =50\frac{rad}{s}$

$B=3\times {10}^{-2}T$

For maximum current emf should be maximum.

So for maximum emf $e=NAB\omega \sin \omega t$

$\sin \omega t=1$

$e_{max}=NAB\omega$

$e_{max}=20\times 200\times {10}^{-4}\times 50\times 3\times {10}^{-2}$

$e_{max}$=$0.6V$

Since resistance is not given,let us consider $R$

$i_{max}$=$\frac{e_{max}}{R}=\frac{0.6}{R}$