Question

A circular current carrying coil has a radius r. Its magnetic dipole moment is proportional to

• A. r
• B. $r^2$
• C. 1/r
• D. 1/$r^2$

Answer 1

Answer: (B)

$r^2$

Magnetic moment $=niA$
$=ni\pi r^2$ $(\because A=\pi r^2)$
So, $M\alpha r^2$