Magnetic Field Due to a Straight Current Carrying Conductor
A circular cu...
Question
A circular current carrying coil has a radius R. The distance from the center of the coil, on the axis, where B will be 18 of its value at the center of the coil is
A
R√3
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B
√3R
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C
2√3R
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D
2R√3
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Solution
The correct option is B√3R B=μ0NiR22(R2+x2)3/2 =μ0Ni2R⋅1[1+x2R2]3/2 =BC⋅1(1+x2R2)3/2[LetBC=μ0Ni2R] ⇒BC8=BC(1+x2R2)3/2[∵B=BC8] ⇒(1+x2R2)3/2=8 ⇒1+x2R2=4 ⇒x2R2=3 ∴x=R√3