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Question

A circular disc has a hole of diameter d1 and an external diameter d2, where d2=3d1. On heating d2 increases by 0.3%. Find d1.

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Solution

Circular disc which has a whole of distance =d1
External distance =d2
Given, d2=3d1
As per question,
Initiald2Finald21001003d2?Finald2=1003×d2100d1=d23(1)
For final value of d2=1003d2100
On putting in equation (1) and we will get,
d1=1003d2100×3d1=0.334d2


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