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Question

A circular disc is rotating about its own axis. An external opposing torque of magnitude 0.02Nm is applied on the disc, due to which it comes to rest in 5 seconds. The initial angular momentum of the disc is:

A
0.1 kgm2s1
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B
0.04 kgm2s1
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C
0.025 kgm2s1
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D
0.01 kgm2s1
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Solution

The correct option is A 0.1 kgm2s1
¯C=0.02N/m
t=5sec
torque is applied for 5sec and torque is rate of change of angular momentum so,
angular momentum lost due to decelaration =¯C×t
=(0.02)×5
=0.1
change in angular momentum = final angular momentum initial angular momentum
0.1=0 Initial angular momentum
Initial angular momentum = 0.1 kg m2/s

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