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Question

A circular disc is rotating in horizontal plane about its own axis at the rate of 210 rpm. A coin of mass 10 gm is placed on the disc at a distance 10 cm from the axis. If the coin does not skid, the frictional force between the coin and the disc is:

A
0.242 N
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B
0.484 N
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C
0.844 N
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D
1.26 N
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Solution

The correct option is B 0.484 N
Friction(f) is balancing the centripetal force
f=mω2r
=10×103×0.1×(210×2π60)2
=0.484N

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