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Question

A circular disc is rotating with constant angular velocity about an axis that passes through the center. A particle '$ P$' is kept at a distance of $ 2m$ from the center and another particle '$ Q$' at a distance of $ 3m$ from the center. Which of these will have higher centripetal acceleration?

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Solution

Step 1: Given data

Distance of particle P from center(RP) =2m

Distance of particle Q from center(RQ) =3m

Let that particle rotate in a circular motion with constant angular velocity ω

Step 2: Applied formulae

The centripetal acceleration is given by :α=ω2R

Since ω is constant, acceleration depends on R

R is the distance from the center

We know, RQ is greater than RP

ω2RQ>ω2RP

Therefore particle Q will have greater centripetal acceleration.


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