A circular disc is rotating with constant $ω = 2$ rad/sec, about an axis passing through its centre. An object is kept at a distance of $^{'} r_{1} = 2 c m^{'}$ from the centre and another object is kept at a distance of $^{'} r_{2} = 1 c m^{'}$ . Find the ratio of their linear speeds.

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Solution

$v = r ω$

$v_{1} = r_{1} ω = 2 \times 2 = \frac{4 c m}{s e c}$

$v_{2} = r_{2} ω = 1 \times 2 = \frac{2 c m}{s e c}$

$\frac{v_{1}}{v_{2}} = \frac{4}{2} = 2$

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A circular disc is rotating with constant ω=2 rad/sec, about an axis passing through its centre. An object is kept at a distance of ′r1=2cm′ from the centre and another object is kept at a distance of ′r2=1cm′. Find the ratio of their linear speeds. ___

v=rω v1=r1ω=2×2=4cmsec v2=r2ω=1×2=2cmsec v1v2=42=2

A circular disc is rotating with constant $ω = 2$ rad/sec, about an axis passing through its centre. An object is kept at a distance of $^{'} r_{1} = 2 c m^{'}$ from the centre and another object is kept at a distance of $^{'} r_{2} = 1 c m^{'}$ . Find the ratio of their linear speeds.

___

$v = r ω$

$v_{1} = r_{1} ω = 2 \times 2 = \frac{4 c m}{s e c}$

$v_{2} = r_{2} ω = 1 \times 2 = \frac{2 c m}{s e c}$

$\frac{v_{1}}{v_{2}} = \frac{4}{2} = 2$