Question

A circular disc of radius $0.2m$ is placed in a uniform magnetic field of induction $\frac{1}{\pi }\left(Wb/m^2\right)$ in such way that its axis makes an angle of ${60}^{\circ }$ with $\overrightarrow{B}$ . The magnetic flux linked with the disc is

• A. $0.08Wb$
  
• B. $0.01Wb$
• C. $0.02Wb$
• D. $0.06Wb$

Answer 1

The correct option is C $0.02Wb$

The magnetic flux linked with the disc is given by:

$\varphi =BAcos\theta =\left(\frac{1}{\pi }\right)\left[\pi \right(0.2{)}^2]cos{60}^o$

$=(0.2{)}^2\times \frac{1}{2}$

$=0.02Wb$