A circular disc of radius 100 mm and mass 1 kg, initially at rest at position A, rolls without slipping down a curved path as shown in figure. The speed v of the disc when it reaches position B is
$\frac{m}{s}$ .
Acceleration due to gravity, $g = \frac{m}{s^{2}}$ .

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Solution

Loss in P.E. = Gain in rotational K.E + gain in translational K.E.
$m g H = \frac{1}{2} I ω^{2} + \frac{1}{2} m v^{2}$

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A circular disc of radius 100 mm and mass 1 kg, initially at rest at position A, rolls without slipping down a curved path as shown in figure. The speed v of the disc when it reaches position B is ms. Acceleration due to gravity, g=ms2.

Loss in P.E. = Gain in rotational K.E + gain in translational K.E. mgH=12Iω2+12mv2

A circular disc of radius 100 mm and mass 1 kg, initially at rest at position A, rolls without slipping down a curved path as shown in figure. The speed v of the disc when it reaches position B is
$\frac{m}{s}$ .
Acceleration due to gravity, $g = \frac{m}{s^{2}}$ .

Loss in P.E. = Gain in rotational K.E + gain in translational K.E.
$m g H = \frac{1}{2} I ω^{2} + \frac{1}{2} m v^{2}$