Question

A circular disc starts slipping without rolling down an inclined plane then its velocity will be :

• A. $gh$
• B. $2gh$
• C. $\sqrt{gh}$
• D. $\sqrt{2gh}$

Answer 1

Answer: (D)

$\sqrt{2gh}$

According to the principle of conservation of energy we have $mgh=\frac{1}{2}m{v}^2$. since there is no rotational energy.
Thus we get $v=\sqrt{2gh}$