A circular disc X of radius R is made from an iron plate of thickness t and another disc Y radius 4R is made from an iron plate of thickness t-4- Then- what is the ratio of their moments of inertia Iy-Ix equal to- Both moments of inertia are about the passing through the center of mass and perpendicular to plane of disc-

The correct option is A 64if 't' is the thickness of the disc #160;R is the radius of the disc ρ is the density of the materialmoment of inertia of disc ...

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Standard XII

Physics

Ideal Gas Equation

A circular di...

Question

A circular disc X of radius R is made from an iron plate of thickness t and another disc Y radius 4R is made from an iron plate of thickness $\frac{t}{4}$ . Then, what is the ratio of their moments of inertia $\frac{I_{y}}{I_{x}}$ equal to? (Both moments of inertia are about the passing through the center of mass and perpendicular to plane of disc):

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Solution

The correct option is A 64
if 't' is the thickness of the disc
R is the radius of the disc
$ρ$ is the density of the material
moment of inertia of disc x
$I_{x} = \frac{1}{2 π R^{4} t ρ} \to 1$
moment of inertia of disc y
$I_{y} = 32 π R^{4} t ρ \to 2$
from $1$ and $2$
$I_{y} = 64 I_{x}$

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The correct option is A 64if 't' is the thickness of the disc R is the radius of the discρ is the density of the materialmoment of inertia of disc xIx=12πR4tρ→1moment of inertia of disc yIy=32πR4tρ→2from1 and 2Iy=64Ix

The correct option is A 64
if 't' is the thickness of the disc
R is the radius of the disc
$ρ$ is the density of the material
moment of inertia of disc x
$I_{x} = \frac{1}{2 π R^{4} t ρ} \to 1$
moment of inertia of disc y
$I_{y} = 32 π R^{4} t ρ \to 2$
from $1$ and $2$
$I_{y} = 64 I_{x}$