Question

A circular field of radius 105 m has a circular path of uniform width 5 m along its boundary. then the area of the path is $3221\frac{3}{7}{m}^2$

If true then enter $1$ and if false then enter $0$

Answer 1

Radius of the inner circular region $=105-5=100m$

Area of the region between two concentric circles with radius of outer circle R, and inner circle

$r=\pi (R^2-r^2)$

So $R=105$ $m$ & $r=100$ $m$.

Hence, the area of the path $=\pi ({105}^2-{100}^2)=\frac{22}{7}(11025-10000)=\frac{22550}{7}=3221\frac{3}{7}{m}^2$