A circular flower bed is surrounded by a path $4 m$ wide bed is $66 m$ . What is the area of this path? $(π = 3.14)$

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Solution

$D = 66 c m$

$w = 4 c m$

diameter of inner ring $= 66 c m$

diameter of outer ring $= 66 + 2 \times 4 = 74 c m$

$∴$ radius of innerring $= \frac{d}{2} = 33 c m (r_{1})$

radius of outer ring $= \frac{d + 2 w}{2} = 37 c m (r_{2})$

Area of path $= π (r_{2}^{2} - r_{1}^{2})$

$= π (37^{2} - 33^{2})$

$= 280 π$

$= 879.6 c m^{2}$

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A circular flower bed is surrounded by a path 4 m wide bed is 66 m. What is the area of this path? (π=3.14)

D=66cmw=4cmdiameter of inner ring =66cmdiameter of outer ring =66+2×4=74cm∴ radius of innerring =d2=33cm(r1)radius of outer ring =d+2w2=37cm(r2)Area of path =π(r22−r21) =π(372−332) =280π =879.6cm2

A circular flower bed is surrounded by a path $4 m$ wide bed is $66 m$ . What is the area of this path? $(π = 3.14)$