A circular flower bed is surrounded by a path $5 m$ wide. If the diameter of the flower bed is $77 m$ , what is the area of the path?

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Solution

$\begin{matrix} \Rightarrow T h e n, a r e a o f p a t h i s = π ({(43.5)}^{2} - (38.5))^{2} A r e a o f p a t h i s = 3.14 \times 410 m^{2} = 1287.4 m^{2} \end{matrix}$

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A circular flower bed is surrounded by a path 5 m wide. If the diameter of the flower bed is 77 m, what is the area of the path?

⇒Then,areaofpathis=π((43.5)2−(38.5))2Areaofpathis=3.14×410m2=1287.4m2

A circular flower bed is surrounded by a path $5 m$ wide. If the diameter of the flower bed is $77 m$ , what is the area of the path?

$\begin{matrix} \Rightarrow T h e n, a r e a o f p a t h i s = π ({(43.5)}^{2} - (38.5))^{2} A r e a o f p a t h i s = 3.14 \times 410 m^{2} = 1287.4 m^{2} \end{matrix}$