A circular grassy plot of land, $42 m$ in diameter, has a path $3.5 m$ wide running around it on the outside. Find the cost of gravelling the path at $R s . 4$ per square metre

R s . 2002

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R s . 2003

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R s . 2004

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R s . 2000

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Solution

The correct option is A $R s . 2002$

Radius of plot = $\frac{42}{2} = 21 m$
Radius of plot with path = 21 + 3.5 = 24.5m
Area of plot = $\frac{22}{7} ({(24.5)}^{2} - {(21)}^{2})$
= $\frac{22}{7} (600.25 - 441)$
= $500.5 m^{2}$
Cost of gravity = Rs. $(500.5 \times 4)$ = Rs. $2002$

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A circular grassy plot of land, 42 m in diameter, has a path 3.5 m wide running around it on the outside. Find the cost of gravelling the path at Rs.4 per square metre

The correct option is A Rs.2002Radius of plot = 422=21mRadius of plot with path = 21 + 3.5 = 24.5mArea of plot = 227((24.5)2−(21)2) = 227(600.25−441) = 500.5m2Cost of gravity = Rs.(500.5×4) = Rs.2002

A circular grassy plot of land, $42 m$ in diameter, has a path $3.5 m$ wide running around it on the outside. Find the cost of gravelling the path at $R s . 4$ per square metre

The correct option is A $R s . 2002$

Radius of plot = $\frac{42}{2} = 21 m$
Radius of plot with path = 21 + 3.5 = 24.5m
Area of plot = $\frac{22}{7} ({(24.5)}^{2} - {(21)}^{2})$
= $\frac{22}{7} (600.25 - 441)$
= $500.5 m^{2}$
Cost of gravity = Rs. $(500.5 \times 4)$ = Rs. $2002$