A circular hole of diameter 0.15 cm is placed 2.1 m from a screen. On illuminating it by light of wavelength $5 \times 10^{- 7} m$ the width of central maxima will be

70 mm

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0.171 mm

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1.71 mm

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1.4 mm

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Solution

The correct option is C
1.71 mm

Width of central maxima = $\frac{2 \times 1.22 λ D}{d} \frac{2 \times 1.22 \times 5 \times 10^{- 7} \times 2.1}{0.15 \times 10^{- 2}} = 1.708 \times 10^{- 3} m = 1.71 m m .$

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[AMU (Med.) 2002]

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A circular hole of diameter 0.15 cm is placed 2.1 m from a screen. On illuminating it by light of wavelength 5×10−7 m the width of central maxima will be

The correct option is C 1.71 mm Width of central maxima = 2×1.22λDd2×1.22×5×10−7×2.10.15×10−2=1.708×10−3 m=1.71 mm.

A circular hole of diameter 0.15 cm is placed 2.1 m from a screen. On illuminating it by light of wavelength $5 \times 10^{- 7} m$ the width of central maxima will be

The correct option is C
1.71 mm

Width of central maxima = $\frac{2 \times 1.22 λ D}{d} \frac{2 \times 1.22 \times 5 \times 10^{- 7} \times 2.1}{0.15 \times 10^{- 2}} = 1.708 \times 10^{- 3} m = 1.71 m m .$