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Moment of Inertia of a Disc

a circular ho...

Question

a circular hole of radius R/2 is cut off from a solid uniform disc of radius R. If the mass of the remaining portion is M , then the moment of inertia of the body about the axis through O and perpendicular to the plane of a disc is

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Q. A circular portion of diameter

R

is cut out from a uniform circular disc of mass

M

R

as shown in figure. The moment of inertia of the remaining (shaded) portion of the disc about an axis passing through the centre O of the disc and perpendicular to its plane is:

A circular portion of radius R/2 is cut from a uniform circular disc of mass M and radius R
as shown in the figure. Find the moment of inertia of the remaining body about an axis
which is perpendicular to the plane of the disc and touches a point on the circumference of the disc as shown.

Q. From a uniform circular disc of radius R and mass

9 M

, a small disc of radius

\frac{R}{3}

is removed as shown in the figure. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through centre of disc is. (Given that moment of inertia of removed portion about the given axis is

M R^{2} / 2

Q. A circular disc of radius R/3 is cut from a circular disc of radius R and mass 9 M as shown. Then moment of inertia of remaining disc about O perpendicular to the plane of the disc is :

Q. From a uniform circular disc of radius R and mass

9 M

, a small disc of radius

\frac{R}{3}

is removed as shown in the figure. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through centre of disc is. (Given that moment of inertia of removed portion about the given axis is

M R^{2} / 2

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