Question

A circular loop of radius 0.0157 m carries a current of 2.0 amp .The magnetic field at the center of the loop is

Answer 1

Step1:Formula used:

The magnetic field due to a circular loop= $B=\raisebox{1ex}{${\mu }_0$}\!\left/ \!\raisebox{-1ex}{$4\mathrm{\pi }$}\right.\raisebox{1ex}{$\times 2\mathrm{\pi i}$}\!\left/ \!\raisebox{-1ex}{$r$}\right.$

Given data:

r=0.0157

I =2.0amp

Step 2:Calculation of magnetic field:

$B={10}^{-7}\times \raisebox{1ex}{$2\mathrm{\pi }\times 2$}\!\left/ \!\raisebox{-1ex}{$0.0157$}\right.$

$=8\times {10}^{-5}Wb/m^2$

Hence, The magnetic field at the center of the loop is $8\times {10}^{-5}Wb/m^2$.