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Question

A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is 15 cm. If a current of 2.0 A flows through the smaller loop, then flux liked with bigger loop is:

A
6×1011 weber
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B
3.3×1011 weber
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C
6.6×109 weber
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D
9.1×1011 weber
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Solution

The correct option is D 9.1×1011 weber

Magnetic field at the centre of the bigger loop due to flow of current is smaller loop is
B=μo4π2πIa2(a2+x2)3/2 (Refer to Image)

Flux through the bigger loop=
ϕ=BA

=μo4π2πIa2(a2+x2)3/2πb2

=107×2π×2×(0.3×102)2[(0.3×102)2+(15×102)2]3/2π(20×102)2

9.11×1011 weber .

1137449_1012852_ans_96064df3c28544bc9fc6a1ca3a95c7cd.PNG

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