A circular loop of radius $2 c m$ , is placed in a time varying magnetic field with rate of $2 T / s e c$ . Then induced electric field in this loop will be:

0

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0.002 V / m

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0.01 V / m

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2 V / m

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Solution

The correct option is B $0.002 V / m$
Given that,

Radius $r = 2 c m$

$\frac{d B}{d t} = 2 T$

We know that

Magnetic flux

$ϕ = B A$

$ϕ = B (π r^{2})$

Now, induced e. m.f

$E = \frac{d ϕ}{d t}$

$E = \frac{d (B π r^{2})}{d t}$

$E = π r^{2} \frac{d B}{d t}$

$E = 3.14 \times {(0.02)}^{2} \times 2$

$E = 0.002 V$

Hence, the induced e. m. f is $0.002 V$

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