Question

A circular loop of rope of length L rotates with uniform angular velocity $\omega$ about an axis through its centre on a horizontal smooth platform. Find the velocity of pulse, with respect to rope, produced due to slight radial displacement.

Answer 1

Length $L=2\pi rr=\frac{L}{2\pi }$

now

$v=r\omega \therefore v=\left(\frac{L}{2\pi }\omega \right)$

$=$ velocity of pulse with respect to rope.