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Question

A circular loop which is in the form of a major arc of a circle is kept in the horizontal plane and a constant magnetic field B is applied in the vertical direction such that the magnetic lines of forces go into the plane. If R is the radius of the circle and it carries a current I in the clockwise direction then the force on the loop will be.
770488_3f681cde420744038d31f1a306ca6cea.png

A
BIR tanα
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B
2 BIR cos(α/2)
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C
2 BIR sin(α/2)
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D
none of these
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Solution

The correct option is C 2 BIR sin(α/2)
Force due to the section AA1 and BB1 is same and opposite.
Hence net force due to these section is zero.
Force due to section A1B1 is F
Length of A1DB1=2A1D=2Rsinα2
F=ϕiμ×B=i(A1DB1)B=2iRBsinα2
Downward direction.
Answer is (option - C).

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