Let the radius of plate is r and area is A.
Given that Δrr×100=k
⇒Δr=kr100
Area of plate, A=πr2
⇒dAdr=ddr(πr2)=2πr
Now, approximate increase in area of plate,
ΔA≈(dAdr)×Δr
⇒ΔA≈2πr×kr100
⇒ΔA≈2kπ100×102[∵r=10cm(given)]
⇒ΔA≈2kπ
∴ Approximate increase in the area of plate is 2kπcm2