A circular park has a path of uniform width around it. The difference between outer and inner circumference of the circular path is 132m. Its width is: Take (π=227)
A
22m
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B
20m
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C
21m
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D
24m
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Solution
The correct option is C21m Given, 2πr2−2πr1=132 ⇒r2−r1=1322π=132×744m=21m i.e., width of the path =21m