Question

A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular park is $132$ m. Its width is

• A. $20$ m
• B. $21$ m
• C. $22$ m
• D. $24$ m

Answer 1

Answer: (B)

$21$ m

Let $r_1$ and $C_1$ be the radius and the circumference of the inner circle.

Let $r_2$ and $C_2$ be the radius and the circumference of the outer circle.

The width of the circular path is $(r_2-r_1)$ m.

Given, $C_2-C_1=132$ m

$\Rightarrow 2\pi r_2-2\pi r_1=132$

$\Rightarrow 2\pi (r_2-r_1)=132$

$\Rightarrow r_2-r_1=\frac{66}{\frac{22}{7}}$

$\Rightarrow r_2-r_1=21$

Thus, width of the circular path is $21$ m.