A circular plate expands when heated from a radius of $5 c m s$ to $5.06 c m$ then the approximate percentage increase in its area is?

0.6

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2.4

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0.12

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Solution

The correct option is C $2.4$
Given, a circular plate expands from 5 cms to 5.06 cms.
Initially, the area is $π r^{2}$
$= 25 π c m^{2}$
After expansion the area is $(5.06)^{2} π$
$= 25.6036 π$
$∴$ percentage increases in its area is
$\frac{25.6036 π - 25 π}{25 π} \times 100$
$= \frac{0.6036}{25} \times 100$
$= 2.4144 %$

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A circular plate expands when heated from a radius of 5 cms to 5.06 cm then the approximate percentage increase in its area is?

The correct option is C 2.4Given, a circular plate expands from 5 cms to 5.06 cms.Initially, the area is πr2=25πcm2After expansion the area is (5.06)2π=25.6036π∴ percentage increases in its area is25.6036π−25π25π×100=0.603625×100=2.4144%

A circular plate expands when heated from a radius of $5 c m s$ to $5.06 c m$ then the approximate percentage increase in its area is?