CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Volume of a Cylinder

A circular pr...

Question

A circular primary clarifier processes an average flow of 5005 $m^{3} / d$ of municipal waste water. The overflow rate is 35 $m^{3} / m^{2} / d$ . The diameter of clarifier shall be

A

13.5 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

12.5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

11.5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

10.5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $13.5 m$
$Overflow rate = \frac{Average flow}{Area}$

$\Rightarrow 35 = \frac{5005}{A}$

$\Rightarrow A = \frac{5005}{35} = 143$

For circular pipe

$A = \frac{π d^{2}}{4}$

$\Rightarrow 143 = \frac{π d^{2}}{4}$

$\Rightarrow d = 13.49 m$

$≃ 13.5 m$

Suggest Corrections

thumbs-up

1

Similar questions

Q. A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of

0.1 m m / s, 0.2 m m / s

1.0 m m / s

respectively. What would be the total percentage of particles removed, if clarifier operates at a Surface Overflow Rate (SOR) of

43.2 m^{3} / m^{2} d

?

Q. A water treatment plant treats

6000 m^{3}

of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of

1.5 m

per hour would produce the desired removal of particles through settling in the clarifier having a depth of

3.0 m

. The volume of the required clarifier, (in

m^{3}

, round off to 1 decimal place) would be

Q. Consider a primary sedimentation tank (PST) in a water treatment plant with Surface Overflow Rate (SOR) of

40 m^{3} / m^{2} / d

. The diameter of the spherical particle which will have

90

percent theoretical removal efficiency in this tank is ________µm.
Assume that settling velocity of the particles in water is described by Stoke's Law.

Given : Density of water

= 1000 k g / m^{3}

,
Density of particle =

2650 K g / m^{3}

g = 9.81 m / s^{2}

.
Kinematic viscosity of water

(v) = 1.10 \times 10^{- 6} m^{2} / s

.

Q. Two identically sized primary settling tanks receive water for type-I settling surface overflow rate (SOR) maintained in the two tanks are

30 m^{3} / s^{2} d

15 m^{3} / m^{2} d

. The lowest diameters of the particles, which shall be settled out completely under SORs of

30 m^{3} / m^{2} d

15 m^{3} / m^{2} d

are designated as

d_{30}

d_{15}

, respectively. The ratio

d_{30} / d_{15}

(round off to two decimal places), is

Q. A municipal corporation is required to treat

1000

m^{3} / d a y

of water. It is found that an overflow rate of 20 m/day will produce a satisfactory removal of the discrete suspended particles at a depth of

3 m

. The diameter (in meters, rounded to the nearest integer) of a circular settling tank designed for the removal of these particles would be.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Volume of Solids

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Volume of a Cylinder

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon