A circular ring of diameter 40cm and mass I kg is rotating about an axis normal to its plane and passing through the (time with a frequency of 10 rotations per second. Calculate the angular momentum about its axis of rotation.

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Solution

$O$ for a circular ring
$I_{a x i s} = M R^{2}$
Since $I$ is the mass of ring
$I V^{2} = M O I$
$I {(0.2)}^{2} = 0.04 I = M O I$ of ring
$w = 10$
angular momentum $= I_{w} = 0.41$
We get, $I_{w} = 0.41.$

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A circular ring of diameter 40cm and mass I kg is rotating about an axis normal to its plane and passing through the (time with a frequency of 10 rotations per second. Calculate the angular momentum about its axis of rotation.

O for a circular ring Iaxis=MR2Since I is the mass of ringIV2=MOII(0.2)2=0.04I=MOI of ringw=10angular momentum =Iw=0.41We get, Iw=0.41.

$O$ for a circular ring
$I_{a x i s} = M R^{2}$
Since $I$ is the mass of ring
$I V^{2} = M O I$
$I {(0.2)}^{2} = 0.04 I = M O I$ of ring
$w = 10$
angular momentum $= I_{w} = 0.41$
We get, $I_{w} = 0.41.$