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Question

A circular ring of mass M and radius R is placed in a gravity free space. A small particle of mass m is placed on the axis of ring at a distance 3R from the centre of the ring. If particle and ring are released from rest. Speed with which particle passes through the centre of the ring is

A
2GMR
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B
GM22mR
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C
GM2(M+m)R
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D
G(M+m)22MR
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Solution

The correct option is C GM2(M+m)R
By COE GMm2R=12MV2+12mV20 ----(1)
By COM MV=mV0 ----(2) solving (1) & (2)
V0=GM2(M+m)R

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