A circular road of radius $1000$ m has banking $45^{o}$ . The maximum safe of a car having mass $2000 k g$ will be if the coefficient of friction of friction between tyre and road i $0.5$

172 m / s

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124 m / s

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99 m / s

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86 m / S

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Solution

The correct option is A $172 m / s$
Given,

$θ = 45^{0}$

$r = 1000 m$

$m = 2000 k g$

$μ = 0.5$

$g = 9.8 m / s^{2}$

The maximum safe velocity for car is,

$v = \sqrt{\frac{r g (t a n θ + μ)}{1 - μ t a n θ}}$

$v = \sqrt{\frac{1000 \times 9.8 (t a n 45^{0} + 0.5)}{1 - 0.5 \times t a n 45^{0}}}$

$v = 171.45 m / s$

Approximately 172 m/s

Suggest Corrections

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45^{\circ}

1000 m

45^{o}

2000 k g

0.5

45^{\circ}

45^{0}

1000 m

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2000 kg

0.3

g = 10 {m/s}^{2}

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