A circular road runs round a circular garden. If the difference between the circumference of the outer circle and the inner circle is $44$ metres, the width(in m) of the road is ....

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Solution

Let the outer and inner radii are $k$ and $r$ respectively.
Width of the road $= R - r$
Now $2 π R - 2 π r = 44 m$
$\Rightarrow 2 π (R - r) = 44$
$R - r = \frac{44}{2 π} = 7 m$

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A circular road runs round a circular garden. If the difference between the circumference of the outer circle and the inner circle is 44 metres, the width(in m) of the road is ....

Let the outer and inner radii are k and r respectively.Width of the road =R−rNow 2πR−2πr=44m⇒2π(R−r)=44R−r=442π=7m

A circular road runs round a circular garden. If the difference between the circumference of the outer circle and the inner circle is $44$ metres, the width(in m) of the road is ....

Let the outer and inner radii are $k$ and $r$ respectively.
Width of the road $= R - r$
Now $2 π R - 2 π r = 44 m$
$\Rightarrow 2 π (R - r) = 44$
$R - r = \frac{44}{2 π} = 7 m$