Question

A circular rod of diameter 30 mm and length 200 mm is subjected to a tensile force. The extension in rod is 0.09 mm and change in diameter is 0.0045 mm. What is the Poisson's ratio of the material of the rod ?

• A. 0.30
• B. 0.32
• C. 0.33
• D. 0.35

Answer 1

The correct option is C 0.33

Poisson's ratio is given by
$\mu =\frac{\text{lateral strain}}{\text{longitudinal strain}}$
$=\frac{\Delta D/D}{\Delta L/L}=\frac{\Delta D}{\Delta L}\times \frac{L}{D}$
$=\frac{0.0045}{30}\times \frac{200}{0.09}=0.33$