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Question

A circular three-pinned arch of span 40 m and a rise of 8m is hinged at the crown and springings. It carries a horizontal load of 100 kN per vertical metre on the left side. The horizontal thrust at the right springing will be

A
800 kN
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B
600 kN
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C
200 kN
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D
400 kN
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Solution

The correct option is C 200 kN

The vertical reaction at B is

VB×40=100×8×4
VB=80 kN
For horizontal thrust at B taking moment of right part about crown (C)

VB×20=H×8
H=80×208=200 kN

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